| Front | A part of the curve with equation \(y=ln(x^2+1)\) is shown in the diagram.Use four rectangles of equal width to find an upper bound for \(∫^6_2ln(x^2+1)dx\).
![]() |
| Back |
![]() |
| Front | Chain rule |
| Back | If y=f(u), where u=g(x), then\(\frac{dy}{dx}=\frac{dy}{du}×\frac{du}{dx}\) |
| Front | Use the equations \(v=u+at \) and \(s=\frac{1}{2}(u+v)t\) to derive an equation for v2 in terms of u, a and s. |
| Back |
![]() |