| Front | - john is healthy; chance of cystic fibrosis is 1/1000,000; what is the probability of him being a carrier- jill is healthy and she had a child w/ cystic fibrosis w/ her ex-husband; now she is w/ john; what is the probability of john + jill's child having cystic fibrosis- if prevalence of hereditary sphero is 1/5000, then what's the prevalence of homozygous- using the letters 'p' and 'q', in an autosomal recessive disease, what is the formula for prevalence of disease, prevalence of normal, prevalence of carrier- for autosomal dominant disease and x-linked recessive disease, what is the formula for prevalence of disease |
| Back | - in autosomal recessive disease, q^2 [q squared] = prevelence of disease; p^2 = prevalence of normal; 2pc = prevalence of carrier- in autosomal dominant disease, prevalence of disease = 2pq- for x-linked recessive, prevalence in male is q and for female is q^2- john being a carrier = 2 * p * q; q^2 = 1/1000,1000, so q = 1/1000; p + q = 1 and so p is (almost) 1; 2 * p * q = 1/500- john + jill's child having cystic fibrosis = prob of jill being a carrier ( = 1; since she had a child w/ cystic fibrosis) * her chance of passing q to the child ( = 1/2) * prob of john being a carrier ( = 1/500) * his chance of passing q to the child (1/2) = 1/2000- in hereditary sphero, 2pq = 1/5000, q = 1/10,000, q^2 = 1/100,000,000 |
"pressure is 80 to 180"